The arithmetic mean of a set of observations | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let $x_1, x_2, \dots, x_n$ be $n$ observations,then the mean is given by $\bar{X} = \frac{1}{n} \sum_{i=1}^{n} x_i$.Let the new observations be $y

Vedclass · Accepted Answer

$\frac{\bar{X} + 10\alpha}{\alpha}$

Vedclass · Answer

(C) Let $x_1, x_2, \dots, x_n$ be $n$ observations,then the mean is given by $\bar{X} = \frac{1}{n} \sum_{i=1}^{n} x_i$.Let the new observations be $y_i = \frac{x_i}{\alpha} + 10$.The mean of the new series $\bar{Y}$ is given by:$\bar{Y} = \frac{1}{n} \sum_{i=1}^{n} \left( \frac{x_i}{\alpha} + 10 \right)$$\bar{Y} = \frac{1}{\alpha} \left( \frac{1}{n} \sum_{i=1}^{n} x_i \right) + \frac{1}{n} (10n)$$\bar{Y} = \frac{\bar{X}}{\alpha} + 10$$\bar{Y} = \frac{\bar{X} + 10\alpha}{\alpha}$

The arithmetic mean of a set of observations is $\bar{X}$. If each observation is divided by $\alpha$ and then increased by $10$,then the mean of the new series is:

Similar Questions

$A$ tiny air bubble in a glass slab $(\mu = 1.5)$ appears from one side to be $6\, cm$ from the glass surface and from the other side,$4\, cm$. The thickness of the glass slab is......$cm$

$A$ nichrome wire $50 \text{ cm}$ long and $1 \text{ mm}^2$ cross-section carries a current of $4 \text{ A}$ when connected to a $2 \text{ V}$ battery. The resistivity of the nichrome wire in $\Omega \cdot \text{m}$ is:

If $\theta = \frac{\pi}{6}$,then the $10^{th}$ term of the series $1 + (\cos \theta + i \sin \theta) + (\cos \theta + i \sin \theta)^2 + (\cos \theta + i \sin \theta)^3 + \dots$ is equal to:

Antrum is a characteristic feature of which follicle?

If the line $2x - 3y + 5 = 0$ is the perpendicular bisector of the line segment joining $(1, -2)$ and $(\alpha, \beta)$,then $\alpha + \beta =$

Vedclass Test Series

Exam Paper Generator

Online Exam Module